This information is part of the Modelica Standard Library maintained by the Modelica Association.

Syntax

Special.erfInv(u);

Description

This function computes the inverse of the complementary error function erfc(u) = 1 - erf(u) with a relative precision of about 1e-15. Therefore, u = erfc(erfcInv(u)) and erfcInv(u) = erfInv(1 - u). Input argument u must be in the range (otherwise an assertion is raised):

0 ≤ u ≤ 2

If u = 2, the function returns -Modelica.Constants.inf.
If u = 0, the function returns Modelica.Constants.inf
The implementation utilizes the formulation of the Boost library (erf_inv.hpp, developed by John Maddock).
Plot of the function:

For more details, see Wikipedia.

Example

erfcInv(1)         // = 0
erfcInv(0.5)       // = 0.4769362762044699
erfInv(1.999999)   // = -3.4589107372909473

See also

erf, erfc, erfInv.

y = erfcInv(u)

u	Type: Real Description: Input argument

y	Type: Real Description: erfcInv(u)